The quotient of the square of a number minus the cubed root of another number and the sum of those two numbers is nine. how can this relationship best be stated algebraically

Answer:[tex]\frac{x^{2} -\sqrt[3]{y}}{x+y}=9[/tex]Step-by-step explanation:we know thatThe quotient means, divide the numerator by the denominatorIn this problem1) The numerator is "the square of a number minus the cubed root of another number"Letx ----> a numbery ----> another numberThe algebraic expression of the numerator of the quotient is [tex]x^{2} -\sqrt[3]{y}[/tex]2) The denominator is "the sum of those two numbers"soThe algebraic expression of the denominator of the quotient is [tex]x+y[/tex]3) The quotient of the square of a number minus the cubed root of another number and the sum of those two numbers is nineEquate the quotient to the number 9sowe have[tex]\frac{x^{2} -\sqrt[3]{y}}{x+y}=9[/tex]